Program: C program to add two numbers
#include<stdio.h>
int main() {
int num1, num2, sum;
printf("\nEnter two numbers: ");
scanf("%d %d", &num1, &num2);
sum = num1 + num2;
printf("Sum: %d", sum);
return(0);
}
Output
Enter two numbers: 4 5
Sum: 9
Program: addition of two numbers in c
#include <stdio.h>
int main() {
int number1, number2, add;
printf("Enter two integer numbers: ");
scanf("%d %d", &number1, &number2);
// calculating sum
add = number1 + number2;
printf("%d + %d = %d", number1, number2, add);
return 0;
}
Output
Enter two integer numbers: 10 10
10 + 10 = 20
In this example, the user is asked to enter two integer numbers and then the program displays the sum of these two numbers.
#include <stdio.h>
int main()
{
int number1, number2, sum;
printf("Enter the first number: ");
scanf("%d", &number1);
printf("Enter the second number: ");
scanf("%d", &number2);
sum = number1 + number2;
printf("Sum of the two numbers are: %d", sum);
return 0;
}
Output
Enter the first number: 10
Enter the second number: 10
Sum of the two numbers are: 20
C program to find the sum of two numbers using a user-defined function. The function adds two numbers and returns the result of the addition.
#include <stdio.h>
int sum2number(int num1, int num2){
return num1+num2;
}
int main()
{
int number1, number2, sum;
printf("Enter the first number: ");
scanf("%d", &number1);
printf("Enter the second number: ");
scanf("%d", &number2);
//Calling the function
sum = sum2number(number1, number2);
printf("The Sum of the entered numbers are: %d", sum);
return 0;
}
Output
Enter the first number: 10
Enter the second number: 10
The Sum of the entered numbers are: 20
You can also use the bitwise operator to find the sum of two numbers.
int sum(int num1, int num2)
{
while (num2 != 0)
{
int carry = num1 & num2;
num1 = num1 ^ num2;
num2 = carry << 1;
}
return a;
}
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In this example, I will show you how we can add two numbers without using the + operator.
#include<stdio.h>
int main()
{
int a,b;
a=10;
b=20;
int sum;
sum=a-(-b);
printf ("Sum of two numbers are %d",sum);
return 0;
}
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